We are testing H₀: ? = 32;versus H_A: ? > 32.If $\overline { \mathrm { X } } = 36$
s = 1.6,and n = 30 at ? = .05,we should reject H₀.

Question

We are testing H₀: ? = 32;versus H_A: ? > 32.If $\overline { \mathrm { X } } = 36$ s = 1.6,and n = 30 at ? = .05,we should reject H₀.

Quizplus · Accepted Answer

We can conduct a one-sample t-test with the following hypotheses: Null hypothesis (H0): μ = 32 Alternative hypothesis (Ha): μ > 32 Using the given sample information, we calculate the test statistic: t = (36 - 32) / (1.6 / sqrt(30)) = 11.18 At a significance level of α = .05 with a one-tailed test (since Ha is one-sided), the critical t-value with 29 degrees of freedom is 1.699. Since our calculated t-value is greater than the critical t-value, we reject the null hypothesis. Therefore, we can conclude that the sample provides enough evidence to reject H₀ in favor of H_A.

We Are Testing H0: ? = 32;versus HA: ? > X‾=36\overline { \mathrm { X } } = 36X=36

We Are Testing H₀: ? = 32;versus H_A: ? > $\overline { \mathrm { X } } = 36$