In a random sample of 651 computer scientists who subscribed to a web-based daily news update,it was found that the average salary was $46,816 with a population standard deviation of $12,557.Calculate a 91 percent confidence interval for the mean salary of computer scientists.
A) $[ \$ 25,469 \quad \$ 68,163 ]$
B) $[ \$ 46,592 \quad \$ 47,040 ]$
C) $[ \$ 46,157 \quad \$ 47,475 ]$
D) $[ \$ 46,783 \quad \$ 46,849 ]$
E) $[ \$ 45,981$$ \quad$$\$ 47,650 ]$

Question

Quizplus · Accepted Answer

The 91% confidence interval is calculated using the formula: $\bar{x} \pm Z \times \frac{\sigma}{\sqrt{n}}$. Here, $\bar{x} = 46,816$, $\sigma = 12,557$, $n = 651$, and the Z-value for 91% confidence is approximately 1.695. Calculating gives the interval $[45,981, 47,650]$.

In a Random Sample of 651 Computer Scientists Who Subscribed [$25,469$68,163][ \$ 25,469 \quad \$ 68,163 ][$25,469$68,163]

In a Random Sample of 651 Computer Scientists Who Subscribed $[ \$ 25,469 \quad \$ 68,163 ]$