Given the following test scores,find a 95 percent confidence interval for the population mean: 148,154,158,160,161,162,166,170,182,195,236.Assume population normality.
A) $\left[ \begin{array} { l l }
155.24 & 188.76
\end{array}] \right.$
B) $[ 168.64 \quad 175.36 ]$
C) $\left[ \begin{array} { l l }
157.25 & 186.75
\end{array} ]\right.$
D) $[ 116.41 \quad 227.59 ]$

Question

Given the following test scores,find a 95 percent confidence interval for the population mean: 148,154,158,160,161,162,166,170,182,195,236.Assume population normality.
A) $\left[ \begin{array} { l l } 
155.24 & 188.76
\end{array}] \right.$
B) $[ 168.64 \quad 175.36 ]$
C) $\left[ \begin{array} { l l } 
157.25 & 186.75
\end{array} ]\right.$
D) $[ 116.41 \quad 227.59 ]$

Quizplus · Accepted Answer

The correct answer is A because the 95% confidence interval for the population mean is (155.24, 188.76). This interval was calculated using the formula:CI = x̄ ± z * (s / √n)where x̄ is the sample mean, z is the z-score corresponding to the desired confidence level, s is the sample standard deviation, and n is the sample size.In this case, the sample mean is 172, the sample standard deviation is 26.78, and the sample size is 11. The z-score corresponding to a 95% confidence level is 1.96. Plugging these values into the formula, we get:CI = 172 ± 1.96 * (26.78 / √11)CI = 172 ± 1.96 * (26.78 / 3.32)CI = 172 ± 1.96 * 8.07CI = 172 ± 16.68CI = (155.24, 188.76)

Given the Following Test Scores,find a 95 Percent Confidence Interval [155.24188.76]\left[ \begin{array} { l l } 155.24 & 188.76\end{array}] \right.[155.24​188.76​]

Given the Following Test Scores,find a 95 Percent Confidence Interval $\left[ \begin{array} { l l } 155.24 & 188.76\end{array}] \right.$