If $\overline { \overline { X } }$

= 5)2, $\bar { R }$
= )3,and n = 4,and if the specifications are [4.6,5.8],is the process capable?
A)Yes
B)No
$$\mathrm { NTL } = 5.2 \pm 3 \left( \frac { 0.3 } { 2.059 } \right) = 4.763 \text { to } 5.637$$

Question

If $\overline { \overline { X } }$

= 5)2, $\bar { R }$
= )3,and n = 4,and if the specifications are [4.6,5.8],is the process capable?
A)Yes
B)No
$$\mathrm { NTL } = 5.2 \pm 3 \left( \frac { 0.3 } { 2.059 } \right) = 4.763 \text { to } 5.637$$

Quizplus · Accepted Answer

The process is capable because the entire specification range of [4.6, 5.8] falls within the calculated NTL range of [4.763, 5.637].

If X‾‾\overline { \overline { X } }X = 5)2 Rˉ\bar { R }Rˉ

If $\overline { \overline { X } }$ = 5)2 $\bar { R }$