Determine How Much Energy Is Released When Polonium-210 Decays According ${ }^{210} \mathrm{Po} \rightarrow{ }^{4} \mathrm{He}+{ }^{206} \mathrm{~Pb}$

Determine how much energy is released when polonium-210 decays according to ${ }^{210} \mathrm{Po} \rightarrow{ }^{4} \mathrm{He}+{ }^{206} \mathrm{~Pb}$ . [Atomic masses: polonium-210 = 209.982857 amu; helium-4 = 4.002603 amu; lead-206 = 205.974449 amu]

A) 4.14 * 10⁹ kJ/mol
B) 7.20 * 10¹¹ kJ/mol
C) 5.22 * 10⁸ kJ/mol
D) 4.66 * 10⁹ kJ/mol
E) 6.43 * 10¹² kJ/mol