Complete and balance the following redox equation using the set of smallest whole-number coefficients. Now sum the coefficients of all species in the balanced equation. (Remember the coefficients that are equal to one.) The sum of the coefficients is BrO₃^-(aq) + Sb³⁺(aq) $\rarr$ Br^-(aq) + Sb⁵⁺(aq) (acidic solution)

Question

Quizplus · Accepted Answer

The unbalanced equation is:

BrO3^- + Sb^5+ → Br^- + Sb^3+

Balance the charge by adding 3 electrons to the right side:

BrO3^- + Sb^5+ + 3e^- → Br^- + Sb^3+

Balance oxygen by adding 4 H2O molecules to the left side:

BrO3^- + Sb^5+ + 3e^- + 4H2O → Br^- + Sb^3+ + 6H+ + 4OH^-

Balance hydrogen by adding 6 H+ ions to the right side:

BrO3^- + Sb^5+ + 3e^- + 4H2O → Br^- + Sb^3+ + 6H2O + 4OH^-

Balance the charge by adding 6 electrons to the right side:

BrO3^- + Sb^5+ + 3e^- + 4H2O → Br^- + Sb^3+ + 6H2O + 10e^- + 4OH^-

Finally, cancel the electrons to get the balanced equation:

BrO3^- + 5Sb^5+ + 6H2O → Br^- + 5Sb^3+ + 10OH^-

Summing the coefficients of all species in the balanced equation gives:

1 + 5 + 6 + 1 + 5 + 10 = 28

So the answer is D, 17.

Complete and Balance the Following Redox Equation Using the Set →\rarr→

Complete and Balance the Following Redox Equation Using the Set $\rarr$