How many coulombs of charge are required to cause reduction of 0.20 mole of Cr³⁺ to Cr

Name: How many coulombs of charge are required to cause reduction of 0.20 mole of Cr 3+ to Cr
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Question

Quizplus · Accepted Answer

To reduce 0.20 mole of Cr³⁺ to Cr, 3 moles of electrons per mole of Cr³⁺ are needed. Thus, 0.20 moles of Cr³⁺ require 0.60 moles of electrons. Using Faraday's constant (96500 C/mol), the charge required is 0.60 moles * 96500 C/mol = 5.8 * 10⁴ C.

How Many Coulombs of Charge Are Required to Cause Reduction