Calculate E^$\circ$_cell for the following electrochemical cell: Ni(s) | Ni²⁺(aq) || Hg₂²⁺(aq) | Hg(l) | Pt(s)

Name: Calculate E $\circ$ cell for the following electrochemical cell: Ni(s) | Ni 2+ (aq) || Hg 2 2+ (aq) | Hg(l) | Pt(s)
Brand: Quizplus
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Question

Quizplus · Accepted Answer

The correct answer is A because the E^$\circ$_cell for the given electrochemical cell is 1.10 V. This can be calculated using the standard reduction potentials of the half-reactions involved in the cell reaction.

Calculate E ∘\circ∘ cell for the Following Electrochemical Cell: Ni(s) | Ni2+(aq) ||

Calculate E^$\circ$_cell for the Following Electrochemical Cell: Ni(s) | Ni²⁺(aq) ||