For the reaction CuS(s) + H2(g) H2S(g) + Cu(s) ,
G f (CuS) = -53.6 kJ/mol
G f (H2S) = -33.6 kJ/mol
H f (CuS) = -53.1 kJ/mol
H f (H2S) = -20.6 kJ/mol
Calculate the value of the equilibrium constant (Kp) at 798 K and 1 atm pressure.
A) 1.77
B) 1.57
C) 1.37
D) 1.17
E) None of the above
Correct Answer:
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