The reaction: 6CO₂(g) + 6H₂O(g) $\rarr$C₆H₁₂O₆(g) + 6O₂(g) is never expected to be spontaneous.

Question

Quizplus · Accepted Answer

The presence of reactants in the product side of the equation indicates that the reaction is not spontaneous, as the products are less stable than the reactants. Additionally, the negative change in Gibbs free energy (∆G) is not expected to be favorable for spontaneous reaction.

The Reaction: 6CO2(g) + 6H2O(g) →\rarr→ C6H12O6(g) + 6O2(g) Is Never Expected to Be Spontaneous

The Reaction: 6CO₂(g) + 6H₂O(g) $\rarr$ C₆H₁₂O₆(g) + 6O₂(g) Is Never Expected to Be Spontaneous