The reaction SiO₂(s) + Pb(s) $\rarr$ PbO₂(s) + Si(s) is spontaneous.
$\Delta$ G^$\circ$_f (PbO₂) = -217 kJ/mol
$\Delta$ G^$\circ$_f (SiO₂) = -856 kJ/mol

Question

The reaction SiO₂(s) + Pb(s) $\rarr$ PbO₂(s) + Si(s) is spontaneous. $\Delta$G^$\circ$_f (PbO₂) = -217 kJ/mol $\Delta$G^$\circ$_f (SiO₂) = -856 kJ/mol

Quizplus · Accepted Answer

The spontaneity of a reaction cannot be determined solely by the Gibbs free energy of formation ($\Delta G_f^\circ$) values of the products and reactants without considering the overall change in Gibbs free energy ($\Delta G^\circ$) for the reaction, which involves both products and reactants.

The Reaction SiO2(s) + Pb(s) →\rarr→ PbO2(s) + Si(s) Is Spontaneous Δ\DeltaΔ

The Reaction SiO₂(s) + Pb(s) $\rarr$ PbO₂(s) + Si(s) Is Spontaneous $\Delta$