25.0 mL of a 0.100 M solution of NH₃ is titrated with 0.250M HCl. After 25.0 mL of the HCl has been added, the resultant solution is:

Name: 25.0 mL of a 0.100 M solution of NH 3 is titrated with 0.250M HCl. After 25.0 mL of the HCl has been added, the resultant solution is:
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Question

Quizplus · Accepted Answer

After adding 25.0 mL of 0.250 M HCl to 25.0 mL of 0.100 M NH3, the moles of HCl (0.00625 mol) exceed the moles of NH3 (0.0025 mol), resulting in an acidic solution after the equivalence point.

250 ML of a 0