Calculate the concentration of chloride ions in a saturated lead(II) chloride (K_sp = 2.4 * 10^-4) solution.

Question

Quizplus · Accepted Answer

The solubility product constant (Ksp) of lead(II) chloride is given as 2.4x10^-4. From this, we can write the following equation:

PbCl2 (s) ⇌ Pb2+ (aq) + 2Cl- (aq)

At saturation, the concentration of Pb2+ ions will be equal to the concentration of Cl- ions. Let the concentration of Cl- ions be x M. Then, the concentration of Pb2+ ions will also be x M.

Using the Ksp expression:

Ksp = [Pb2+][Cl-]^2

2.4x10^-4 = (x)(x)^2 = x^3

x = 7.8x10^-3 M

Therefore, the concentration of chloride ions in a saturated lead(II) chloride solution is 7.8x10^-3 M or 7.8x10^-2 mM. The closest answer choice is (E).

Calculate the Concentration of Chloride Ions in a Saturated Lead(II)