Calculate the molar solubility of silver carbonate. (K_sp (Ag₂CO₃ = 8.1 x 10^-12))

Question

Quizplus · Accepted Answer

The Ksp value given for silver carbonate is 8.1 x 10^-12. Using the stoichiometry of the balanced equation (Ag2CO3 ⇌ 2Ag+ + CO32-), we can assume that x moles of Ag2CO3 dissolve to form 2x moles of Ag+ ions and x moles of CO32- ions. Therefore, the Ksp expression can be written as Ksp = (2x)^2 (x) = 4x^3. Plugging in the Ksp value given, we get: 
8.1 x 10^-12 = 4x^3 
Solving for x, we get x = 1.31 x 10^-4 M, which is the molar solubility of silver carbonate. Therefore, the best choice is B.

Calculate the Molar Solubility of Silver Carbonate