An environmental chemist obtained a 200. mL sample of lake water believed to be contaminated with a single monoprotic strong acid. Titrating this sample with a 0.0050 M NaOH(aq) required 7.3 mL of the NaOH solution to reach the endpoint. What is the concentration of H⁺ in the lake

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The correct answer is A because the concentration of H+ in the lake water can be calculated using the formula: [H+] = (MNaOH * VNaOH) / Vlake, where MNaOH is the molarity of the NaOH solution, VNaOH is the volume of NaOH solution used in the titration, and Vlake is the volume of the lake water sample. Plugging in the given values, we get: [H+] = (0.0050 M * 0.0073 L) / 0.200 L = 1.8 * 10^-4 M.

An Environmental Chemist Obtained a 200