The equilibrium constant expression for the reaction 2BrF₅ (g) $\rightleftharpoons$ Br₂ (g) + 5F₂ (g) is

Question

Quizplus · Accepted Answer

The equilibrium constant expression is written by raising the concentrations of the products to their stoichiometric coefficients and dividing by the concentrations of the reactants raised to their respective stoichiometric coefficients. Therefore, the correct expression is: K_c = [Br₂] [F₂]⁵ / [BrF₅]². Option A is incorrect as the stoichiometric coefficient of BrF₅ is 1 and not 2. Option C is incorrect as the stoichiometric coefficient of F₂ is 5 and not 12. Option D is incorrect as the stoichiometric coefficient of Br₂ is 2 and not 1, and 5 is written in the denominator instead of the numerator. Option E is incorrect as it has incorrect stoichiometric coefficients and an unnecessary multiplication of 5 in the denominator.

The Equilibrium Constant Expression for the Reaction 2BrF5 (G) ⇌\rightleftharpoons⇌ Br2 (G) + 5F2 (G) Is A) Kc = [Br2]

The Equilibrium Constant Expression for the Reaction 2BrF₅ (G) $\rightleftharpoons$ Br₂ (G) + 5F₂ (G) Is
A) K_c = [Br₂]