K_p for the reaction 4CuO(s) $\rightleftharpoons$ 2Cu₂O(s) + O₂(g) is 0.49 at 1024^$\circ$C. Calculate K_c at this temperature

Question

Quizplus · Accepted Answer

The equilibrium constant (Kc) is calculated by the following expression:

Kc = [CuS12][O2] / [CuO]4

We are given that at 1024°F, Kp = 0.49. We can calculate Kc using the following equation:
Kp = Kc(RT)^(Δn)

where Δn is the difference in the number of moles of gaseous products and reactants, in this case 1 - 0 = 1.

Therefore, Kc = Kp / (RT)^(Δn)
= 0.49 / (R x 1024°C)^(1-0)
= 4.6 x 10^-3

Therefore, the answer is D (4.6 x 10^-3).

Kp for the Reaction 4CuO(s) ⇌\rightleftharpoons⇌ 2Cu2O(s) + O2(g) Is 0 ∘\circ∘