For the reaction at equilibrium: 3Fe(s) + 4H 2 O(g) ⇌ Fe 3 O 4 (s) + 4H 2 (g), removing some of the product, Fe 3 O 4 (s), would:

Removing a solid product does not affect the equilibrium position because solids do not appear in the expression for the equilibrium constant.

For the reaction at equilibrium: 3Fe(s) + 4H 2 O(g) ⇌ Fe 3 O 4 (s) + 4H 2 (g), removing some of the product, Fe 3 O 4 (s), would:

Removing a solid product does not affect the equilibrium position because solids do not appear in the expression for the equilibrium constant.

Solved

For the Reaction at Equilibrium: 3Fe(s) + 4H₂O(g) ⇌ Fe₃O₄(s)

Question 53

Multiple Choice

For the reaction at equilibrium: 3Fe(s) + 4H₂O(g) ⇌ Fe₃O₄(s) + 4H₂(g) , removing some of the product, Fe₃O₄(s) , would:

A) Shift the equilibrium to the right
B) Shift the equilibrium to the left
C) Increase the value of the equilibrium constant, K
D) Decrease the value of the equilibrium constant, K
E) Cause no change

Correct Answer:

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For the Reaction at Equilibrium: 3Fe(s) + 4H2O(g) ⇌ Fe3O4(s)

For the Reaction at Equilibrium: 3Fe(s) + 4H₂O(g) ⇌ Fe₃O₄(s)