What is the percent CdSO₄ by mass in a 1.00 m aqueous CdSO₄ solution A) 1.00 * 10^-3 % B) 0.100 % C) 17.2 % D) 20.8 % E) 24.4 %

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Quizplus · Accepted Answer

A 1.00 m solution means there is 1 mole of solute per kilogram of solvent. The molar mass of CdSO4 (cadmium sulfate) is approximately 208 g/mol. Therefore, in a 1.00 m solution, there are 208 grams of CdSO4 per 1000 grams of water. The percent by mass is calculated as (mass of solute / (mass of solute + mass of solvent)) * 100 = (208 / (208 + 1000)) * 100 = 17.2%.

What Is the Percent CdSO4 by Mass in a 1

What Is the Percent CdSO₄ by Mass in a 1