How many grams of propanol (C₃H₇OH, 60.10 g/mol) would be needed to make 750 mL of a solution with an osmotic pressure of 25 atm at 25^$\circ$C (R = 0.0821 L·atm/K·mol) A) 26 g B) 46 g C) 66 g D) 86 g E) None of the above

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The Answer of How many grams of propanol (C₃H₇OH, 60.10 g/mol) would be needed to make 750 mL of a solution with an osmotic pressure of 25 atm at 25^$\circ$C (R = 0.0821 L·atm/K·mol) A) 26 g B) 46 g C) 66 g D) 86 g E) None of the above

How Many Grams of Propanol (C3H7OH, 60 ∘\circ∘ C (R = 0

How Many Grams of Propanol (C₃H₇OH, 60 $\circ$ C (R = 0