The N - N - H bond angles in hydrazine N₂H₄ are 112^$\circ$. What is the hybridization of the nitrogen orbitals predicted by valence bond theory A) sp B) sp² C) sp³ D) sp⁴ E)None of the above

Question

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The observed bond angles suggest that the nitrogen orbitals in hydrazine are hybridized. The hybridization scheme must account for four orbitals, which are used to form bonds with the two hydrogens and the two nitrogen atoms in the molecule. The best hybridization scheme for this is sp3. Each nitrogen atom in the molecule is surrounded by three orbitals in a trigonal planar arrangement and one orbital pointing towards the other nitrogen atom. Therefore, the correct choice is C, which corresponds to sp3 hybridization.

The N - N - H Bond Angles in Hydrazine ∘\circ∘

The N - N - H Bond Angles in Hydrazine $\circ$