A 135 g sample of H₂O at 85^$\circ$C is cooled. The water loses a total of 15 kJ of energy in the cooling process. What is the final temperature of the water The specific heat of water is 4.184 J/g·^$\circ$C.

Question

Quizplus · Accepted Answer

The energy lost (15,000 J) is equal to the mass (135 g) times the specific heat (4.184 J/g°C) times the change in temperature. Solving for the change in temperature gives a decrease of approximately 27°C, so the final temperature is 85°C - 27°C = 58°C.

A 135 G Sample of H2O at 85 ∘\circ∘ C Is Cooled

A 135 G Sample of H₂O at 85^$\circ$C Is Cooled