A 0.3423 g sample of pentane, C₅H₁₂, was burned in a bomb calorimeter. The temperature of the calorimeter and the 1.000 kg of water contained therein rose from 20.22^$\circ$C to 22.82^$\circ$C. The heat capacity of the calorimeter is 2.21 kJ/^$\circ$C. The heat capacity of water = 4.184 J/g·^$\circ$C. What is the heat of combustion, in kilojoules, per gram of pentane

Question

Quizplus · Accepted Answer

The heat of combustion is the amount of heat released when one gram of a substance is burned completely. In this case, the heat of combustion of pentane is the amount of heat released when one gram of pentane is burned completely in a bomb calorimeter. The heat of combustion can be calculated using the following equation:```Q = mC_pΔT```where:* Q is the heat of combustion (in joules)* m is the mass of the substance (in grams)* C_p is the heat capacity of the substance (in joules per gram per degree Celsius)* ΔT is the change in temperature (in degrees Celsius)In this case, the mass of the pentane is 0.3423 g, the heat capacity of the pentane is 2.21 kJ/^$\circ$C, and the change in temperature is 22.82^$\circ$C - 20.22^$\circ$C = 2.6^$\circ$C. Substituting these values into the equation, we get:```Q = (0.3423 g)(2.21 kJ/^$\circ$C)(2.6^$\circ$C) = 1.87 kJ```Therefore, the heat of combustion of pentane is 1.87 kJ/g.

A 03423 G Sample of Pentane, C5H12, Was Burned in a a Bomb

A 03423 G Sample of Pentane, C₅H₁₂, Was Burned in a a Bomb