A 707 mg sample of a gas containing only carbon and oxygen occupies a volume of 452 mL at 63^$\circ$C and 745 mmHg. Identify the gas in the sample. (R = 0.08206 L*atm/K*mol) A) CO B) CO₂ C) CO₃^2- D) C₂O E) C₂O₂

Question

Quizplus · Accepted Answer

To identify the gas, use the ideal gas law to find the molar mass. Convert the conditions to standard units: T = 336 K, P = 0.980 atm, V = 0.452 L. Using PV = nRT, calculate n = PV/RT = (0.980 * 0.452) / (0.08206 * 336) = 0.016 mol. The molar mass is 707 mg / 0.016 mol = 44.2 g/mol, which matches CO₂.

A 707 Mg Sample of a Gas Containing Only Carbon ∘\circ∘

A 707 Mg Sample of a Gas Containing Only Carbon $\circ$