What is the pressure (mmHg) of the sample of gas trapped in the closed-tube mercury manometer shown below if atmospheric pressure is 751 mmHg and h = 17.3 cm
A) 173 mmHg
B) 273 mmHg
C) 373 mmHg
D) 473 mmHg
E) None of the Above

Question

What is the pressure (mmHg) of the sample of gas trapped in the closed-tube mercury manometer shown below if atmospheric pressure is 751 mmHg and h = 17.3 cm 
A) 173 mmHg 
B) 273 mmHg 
C) 373 mmHg 
D) 473 mmHg 
E) None of the Above

Quizplus · Accepted Answer

The pressure of the gas can be calculated using the equation: 
Pgas = Patm + h

where Pgas is the pressure of the gas, Patm is the atmospheric pressure, and h is the height difference between the two arms of the manometer.

In this case, the height difference is given as h = 17.3 cm. And the atmospheric pressure is given as Patm = 751 mmHg.

To convert the height from cm to mmHg, we need to multiply it by the conversion factor 1 cm = 10 mmHg. So, h = 17.3 cm x 10 mmHg/cm = 173 mmHg.

Therefore, the pressure of the gas is:
Pgas = Patm + h = 751 mmHg + 173 mmHg = 924 mmHg.

The correct answer is A) 173 mmHg.

What Is the Pressure (MmHg) of the Sample of Gas