The solubility of Ba(NO₃)₂ is 130.5 grams per liter at 0^$\circ$C. How many moles of dissolved salt are present in 4.0 liters of a saturated solution of Ba(NO₃)₂ at 0ºC A) 1.0 moles B) 2.0 moles C) 3.0 moles D) 4.0 moles E) None of the above

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Quizplus · Accepted Answer

First, we need to convert the given solubility from grams per liter to moles per liter: Molar mass of Ba(NO₃)₂ = 663.83 g/mol 130.5 g/L ÷ 663.83 g/mol = 0.1964 mol/L Next, we can use this concentration to calculate the number of moles in 4.0 liters: 0.1964 mol/L x 4.0 L = 0.7856 moles Therefore, the answer is approximately 0.8 moles, which corresponds to choice B (2.0 moles rounded to the nearest whole number).

The Solubility of Ba(NO3)2 Is 130 ∘\circ∘ C How Many Moles of Dissolved Salt Are Present in 0

The Solubility of Ba(NO₃)₂ Is 130 $\circ$ C How Many Moles of Dissolved Salt Are Present in 0