What is the theoretical yield of vanadium, in moles, that can be produced by the reaction of 2.0 moles of V₂O₅ with 6.0 moles of calcium based on the chemical reaction below
V₂O₅(s) + 5Ca(l) $\rarr$ 2V(l) + 5CaO(s)

Question

What is the theoretical yield of vanadium, in moles, that can be produced by the reaction of 2.0 moles of V₂O₅ with 6.0 moles of calcium based on the chemical reaction below
V₂O₅(s) + 5Ca(l)

\rarr

2V(l) + 5CaO(s)

Quizplus · Accepted Answer

According to the balanced chemical equation, 1 mole of V₂O₅ reacts with 5 moles of Ca to produce 2 moles of V. Thus, 2 moles of V₂O₅ reacts with 5 × 2 = 10 moles of Ca to produce 2 × 2 = 4 moles of V. Therefore, the theoretical yield of V when 2.0 moles of V₂O₅ reacts with 6.0 moles of Ca is (4/10) × 6.0 = 2.4 moles of V. Therefore, the best choice is D.

What Is the Theoretical Yield of Vanadium, in Moles, That →\rarr→

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