One way of obtaining pure sodium carbonate is through the decomposition of the mineral trona, Na ₃(CO₃) (HCO₃) $\times$ 2H₂O, as shown in the following reaction: 2Na₃(CO₃) (HCO₃) $\rarr$ 2H₂O(s) $\rarr$ 3Na₂CO₃(s) + CO₂(g) + 5H₂O(g)
When 15 metric tons (1 * 10³ kg) of trona is decomposed, 11 metric tons of Na₂CO₃ is recovered. What is the percent yield of this reaction?
(1 metric ton = 10³ kg)

Question

One way of obtaining pure sodium carbonate is through the decomposition of the mineral trona, Na ₃(CO₃) (HCO₃)

\times

2H₂O, as shown in the following reaction: 2Na₃(CO₃) (HCO₃)

\rarr

2H₂O(s)

\rarr

3Na₂CO₃(s) + CO₂(g) + 5H₂O(g)
When 15 metric tons (1 * 10³ kg) of trona is decomposed, 11 metric tons of Na₂CO₃ is recovered. What is the percent yield of this reaction?
(1 metric ton = 10³ kg)

Quizplus · Accepted Answer

The Answer of One way of obtaining pure sodium carbonate is through the decomposition of the mineral trona, Na ₃(CO₃)(HCO₃)$\times$2H₂O, as shown in the following reaction: 2Na₃(CO₃)(HCO₃)$\rarr$2H₂O(s) $\rarr$3Na₂CO₃(s) + CO₂(g) + 5H₂O(g) When 15 metric tons (1 * 10³ kg) of trona is decomposed, 11 metric tons of Na₂CO₃ is recovered. What is the percent yield of this reaction? (1 metric ton = 10³ kg)

One Way of Obtaining Pure Sodium Carbonate Is Through the Decomposition