What is the theoretical yield of PI₃ if 48.0 g of I₂ are reacted with an excess of phosphorus according to the following chemical equation?
2P(s) + 3I₂(s) $\rarr$ 2PI₃(s)

Question

What is the theoretical yield of PI₃ if 48.0 g of I₂ are reacted with an excess of phosphorus according to the following chemical equation? 2P(s) + 3I₂(s) $\rarr$ 2PI₃(s)

Quizplus · Accepted Answer

The molar mass of I2 is approximately 253.8 g/mol. Thus, 48.0 g of I2 is 48.0 g / 253.8 g/mol = 0.189 mol. According to the balanced equation, 3 moles of I2 produce 2 moles of PI3. Therefore, 0.189 mol of I2 will produce (2/3) * 0.189 mol = 0.126 mol of PI3. The molar mass of PI3 is approximately 411.7 g/mol, so the theoretical yield is 0.126 mol * 411.7 g/mol = 51.9 g.

What Is the Theoretical Yield of PI3 If 48 →\rarr→ 2PI3(s) A) 51

What Is the Theoretical Yield of PI₃ If 48 $\rarr$ 2PI₃(s)
A) 51