Acetylene gas, HCCH(g), can be generated in the laboratory by adding calcium carbide to excess water, as shown in the following reaction CaC₂(s) + H₂O(l) $\rarr$ HCCH(g) + CaO(s) How many grams of CaC₂ would be required to generate 0.20 moles of HCCH(g)

Question

Quizplus · Accepted Answer

We start with the given amount of HCCH, which is 0.20 moles. Then, using the balanced chemical equation, we can set up a mole ratio between CaC2 and HCCH:

1 mole of CaC2 produces 1 mole of HCCH

This means that to produce 0.20 moles of HCCH, we need 0.20 moles of CaC2.

To convert from moles to grams, we use the molar mass of CaC2:

1 mole of CaC2 = 64 g of CaC2

0.20 moles of CaC2 = 0.20 x 64 = 12.8 g of CaC2

Therefore, we need 13 g of CaC2 to generate 0.20 moles of HCCH.

Acetylene Gas, HCCH(g), Can Be Generated in the Laboratory by Adding