The unit improvement factor for a 60% learning curve at 25 units is 0.0933.The first and second timings of a person doing a job are 5 minutes and 3 minutes respectively.Which of the below is the learning-adjusted time estimate for unit number 25?
A)0.4665 minutes
B)0.0933 minutes
C)4.665 minutes
D)9.33 minutes
E)3 minutes

Question

Quizplus · Accepted Answer

The formula for learning-adjusted time estimate is:
LAT = ST (unit improvement factor)^log (cumulative units produced/units for first timing)
Here, ST (Standard time) for the first timing is 5 minutes and for the second timing is 3 minutes.
Using the given unit improvement factor of 0.0933, we can calculate the LAT for 25 units:
LAT = 3 * (0.0933)^log (25/1)
LAT = 3 * 0.0933^3.249
LAT = 0.4665 minutes
Therefore, the learning-adjusted time estimate for unit number 25 is 0.4665 minutes, which corresponds to option A.

The Unit Improvement Factor for a 60% Learning Curve at 25