For an exam with a mean of M = 74 and a standard deviation of s = 8,Mary has a score of X = 80,Bob's score corresponds to z = +1.50,and Sue's score is located above the mean by 10 points.If the students are placed in order from smallest score to largest score,what is the correct order?
A)Bob, Mary, Sue
B)Sue, Bob, Mary
C)Mary, Bob, Sue
D)Mary, Sue, Bob

Question

For an exam with a mean of M = 74 and a standard deviation of s = 8,Mary has a score of X = 80,Bob's score corresponds to z = +1.50,and Sue's score is located above the mean by 10 points.If the students are placed in order from smallest score to largest score,what is the correct order?​
A)Bob, Mary, Sue​
B)​Sue, Bob, Mary
C)​Mary, Bob, Sue
D)​Mary, Sue, Bob

Quizplus · Accepted Answer

Mary's score is 80. Bob's score, with a z-score of +1.50, can be calculated using the formula for a z-score: $z = \frac{(X - M)}{s}$. Plugging in Bob's z-score and the given mean (M) and standard deviation (s), we get $1.50 = \frac{(X - 74)}{8}$. Solving for X gives Bob's score as 86. Sue's score is 10 points above the mean, so it's 74 + 10 = 84. Therefore, the order from smallest to largest is Mary (80), Sue (84), Bob (86).

For an Exam with a Mean of M = 74