Use the Hardy-Weinberg equations: p + q = 1 and p² + 2pq + q² = 1.If the dominant allele frequency is 0.8,then what percent of the population will be homozygous recessive?

Question

Quizplus · Accepted Answer

The frequency of the recessive allele (q) is 1 - 0.8 = 0.2. The percentage of the population that is homozygous recessive is q^2 = (0.2)^2 = 0.04, or 4%.

Use the Hardy-Weinberg Equations: P + Q = 1 and P2

Use the Hardy-Weinberg Equations: P + Q = 1 and P²