A car whose initial speed is 40 m/s undergoes a constant acceleration of -5 m/s² when its brakes are applied.In the first 6 s after the brakes are applied, the car travels A)150 m. B)180 m. C)210 m. D)330 m.

Question

Quizplus · Accepted Answer

Explanation:Using the equation of motion, s = ut + 1/2 at^2, where s is the distance traveled, u is the initial velocity, a is the acceleration, and t is the time, we can find the distance traveled by the car in the first 6 s after the brakes are applied.s = ut + 1/2 at^2s = 40 m/s * 6 s + 1/2 * (-5 m/s^2) * (6 s)^2s = 240 m - 90 ms = 150 mTherefore, the car travels 150 m in the first 6 s after the brakes are applied.

A Car Whose Initial Speed Is 40 M/s Undergoes a Constant