A 3000-kg truck accelerates from 10 m/s to 30 m/s in 8 s. The net force on the truck is
A) 765 N.
B) 7500 N.
C) 11,250 N.
D) 15,000 N.

Question

Quizplus · Accepted Answer

The net force on the truck can be calculated using Newton's second law, $F = ma$, where $m$ is the mass and $a$ is the acceleration. First, find the acceleration: $a = \frac{\Delta v}{\Delta t} = \frac{30\,m/s - 10\,m/s}{8\,s} = 2.5\,m/s^2$. Then, $F = 3000\,kg \times 2.5\,m/s^2 = 7500\,N$.

A 3000-Kg Truck Accelerates from 10 M/s to 30 M/s