A 20.0 g sample of aluminum (specific heat = 0.902 J g^-1 °C^-1) with an initial temperature of 48.6°C is heated with 427 J of energy. What is the final temperature of the sample?

Question

Quizplus · Accepted Answer

The formula for calculating the final temperature is:
ΔT = Q / (m * c)
Where Q is the heat energy, m is the mass, and c is the specific heat capacity.
Substituting the given values,
ΔT = 427 J / (20.0 g * 0.902 J g-1 °C-1)
ΔT = 23.7 °C
Therefore, the final temperature is:
T final = T initial + ΔT
T final = 48.6°C + 23.7°C
T final = 72.3°C
So, the answer is B.

A 200 G Sample of Aluminum (Specific Heat = 0