A 50.0 mL sample of 0.108 M H₂SO₄ is diluted to 250.0 mL. What is its new molarity?

Question

Quizplus · Accepted Answer

To calculate the new molarity, we use the formula:

M1V1 = M2V2

where M1 = 0.108 M (initial molarity), V1 = 50.0 mL (initial volume), V2 = 250.0 mL (final volume), and we are solving for M2 (final molarity).

Plugging in these values, we get:

(0.108 M)(50.0 mL) = M2(250.0 mL)

M2 = (0.108 M)(50.0 mL) / 250.0 mL
M2 = 0.0216 M

Therefore, the new molarity is 0.0216 M, which corresponds to choice A).

A 500 ML Sample of 0