Determine the chloride ion concentration in a solution containing 50.0 g MgCl₂ dissolved in 1500 mL of solution.

Question

Quizplus · Accepted Answer

The molecular weight of MgCl2 is approximately 95.21 g/mol. To find the moles of MgCl2 in 50.0 g, divide the mass by the molar mass: 50.0 g / 95.21 g/mol ≈ 0.525 mol. Since each formula unit of MgCl2 releases two chloride ions, the total moles of chloride ions will be 2 * 0.525 mol = 1.05 mol. The volume of the solution is 1500 mL, which is 1.5 L. The concentration of chloride ions is then 1.05 mol / 1.5 L = 0.700 M.

Determine the Chloride Ion Concentration in a Solution Containing 50