At 20°C, a sample of gas has a volume of 2.51 L at 795 torr. What is the new pressure (in atm) if the volume is increased to 6.46 L at the same temperature?

Question

Quizplus · Accepted Answer

Using Boyle's Law (P1V1 = P2V2), where P1 = 795 torr, V1 = 2.51 L, V2 = 6.46 L, and P2 is the unknown pressure. First, convert 795 torr to atm (1 atm = 760 torr), so P1 = 795 torr / 760 torr/atm = 1.046 atm. Then, solve for P2: P2 = P1V1/V2 = (1.046 atm)(2.51 L) / 6.46 L = 0.406 atm.

At 20°C, a Sample of Gas Has a Volume of 2.51