What volume (in L) of oxygen at 298K and 1.50 atm is required for the complete combustion of 25.0 g of hexane? The value of R = 0.0821 L atm mol^-1 K^-1.

Name: What volume (in L) of oxygen at 298K and 1.50 atm is required for the complete combustion of 25.0 g of hexane? The value of R = 0.0821 L atm mol -1 K -1 .
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The Answer of What volume (in L) of oxygen at 298K and 1.50 atm is required for the complete combustion of 25.0 g of hexane? The value of R = 0.0821 L atm mol^-1 K^-1.

What Volume (In L) of Oxygen at 298K and 1