If 7.63 g of an unknown gas occupies 79.1 mL at 25.02°C and 7.55 atm of pressure, what is the molar mass of the gas? The value of R = 0.0821 L atm mol^-1 K^-1.

Question

Quizplus · Accepted Answer

To find the molar mass, use the ideal gas law: PV = nRT. Convert 79.1 mL to 0.0791 L and 25.02°C to 298.17 K. Solve for n (moles): n = PV/RT = (7.55 atm * 0.0791 L) / (0.0821 L atm mol^-1 K^-1 * 298.17 K) = 0.0245 mol. Molar mass = mass/n = 7.63 g / 0.0245 mol = 312 g/mol.

If 763 G of an Unknown Gas Occupies 79