A researcher wanted to compare eye color distributions of babies born with a birth defect with babies who did not have the birth defect.26 babies with the defect were matched on gender,race,and age with 52 babies without the defect.The frequency of different eye colors as a function of the presence or absence of the defects was as follows:
Eye Color
Group Dark Medium Light
Defect 1 6 19
No Defect 15 13 24
If a baby was randomly selected from those participating in the study,the likelihood of that baby having dark eyes is ____.
A)1/16
B)35/78
C)16/78
D)1/26 + 15/52

Question

Quizplus · Accepted Answer

The total number of babies is 26 (with defect) + 52 (without defect) = 78. The number of babies with dark eyes is 1 (with defect) + 15 (without defect) = 16. Therefore, the likelihood of a randomly selected baby having dark eyes is 16/78.

A Researcher Wanted to Compare Eye Color Distributions of Babies