Determine the mass of precipitate (in grams) that forms when 425.1 mL of 0.122 M KI solution is reacted with excess Pb(NO3) 2 solution. 2KI(aq) + Pb(NO3) 2(aq) → PbI2(s) + 2KNO3(aq)
A) 5.19 g
B) 2.59 g
C) 12.0 g
D) 3.48 g
E) 9.55 g
Correct Answer:
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