Determine the volume of a 0.175 M Al(NO₃)₃ solution that contains 0.0591 moles of Al(NO₃)₃.

Name: Determine the volume of a 0.175 M Al(NO 3 ) 3 solution that contains 0.0591 moles of Al(NO 3 ) 3 .
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Question

Quizplus · Accepted Answer

We can use the formula:
moles = concentration x volume
Rearranging for volume:
volume = moles / concentration

Substituting the given values:
moles = 0.0591 mol
concentration = 0.175 M

volume = 0.0591 / 0.175
volume = 0.338 L = 338 mL

Therefore, the answer is D) 338 mL.

Determine the Volume of a 0