Determine the mass of Sr(C₂H₃O₂)₂ that contains 2.780 Χ 10²³ atoms of carbon.

Question

Quizplus · Accepted Answer

To find the mass of Sr(CS1U1B12S1U1B0HS1U1B13S1U1B0OS1U1B12S1U1B0)S1U1B12S1U1B0 that contains 2.780 Χ 10S1U1P123S1S1P0 atoms of carbon, we need to first find the molar mass of the compound and then use it to calculate the mass.

The molar mass of Sr(CS1U1B12S1U1B0HS1U1B13S1U1B0OS1U1B12S1U1B0)S1U1B12S1U1B0 can be calculated by adding the atomic masses of all the atoms in the formula. The atomic masses of the elements present in the compound are:

Sr: 87.62 g/mol
C: 12.01 g/mol
S: 32.07 g/mol
H: 1.01 g/mol
O: 16.00 g/mol

Using these atomic masses, we can calculate the molar mass of the compound as:

Molar mass = (87.62 g/mol) + (12.01 g/mol x 23) + (32.07 g/mol x 26) + (1.01 g/mol x 13) + (16.00 g/mol x 12)
= 1923.43 g/mol

Now, using Avogadro's number, we can determine the number of moles of the compound that contains 2.780 Χ 10S1U1P123S1S1P0 atoms of carbon:

Number of moles = (2.780 Χ 10S1U1P123S1S1P0 atoms of carbon) / (6.022 Χ 10S1U1P23S1S1P0 atoms/mol) / (23 molecules of carbon per molecule of compound)
= 0.0195 mol

Finally, we can calculate the mass of the compound as:

Mass = Number of moles x Molar mass
= 0.0195 mol x 1923.43 g/mol
= 37.51 g

Therefore, the best choice is D) 94.96 g, as it is closest to the calculated mass of the compound.

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