In the following equation,what is the ratio of free radioactive (*)antigen to free patient antigen (the ratio of y/z)after addition of the antibody and after all reactants have reached equilibrium??10 Ag* + 5 Ag + 3 Ab --- (w)Ag*Ab + (x)AgAb + (y)Ag* + (z)Ag

Question

In the following equation,what is the ratio of free radioactive (*)antigen to free patient antigen (the ratio of y/z)after addition of the antibody and after all reactants have reached equilibrium??10 Ag* + 5 Ag + 3 Ab ---> (w)Ag*Ab + (x)AgAb + (y)Ag* + (z)Ag

Quizplus · Accepted Answer

The equilibrium constant for the reaction is:K = [Ag*Ab][AgAb]/[Ag*][Ag][Ab]^3At equilibrium, the ratio of free radioactive antigen to free patient antigen is:y/z = [Ag*]/[Ag] = K/[Ab]^3Since the antibody concentration is constant, the ratio of y/z is also constant. Therefore, the correct answer is A) 2:1.

In the Following Equation,what Is the Ratio of Free Radioactive