How many moles of NH₃ are there in 77.5 g of NH₃ A) 0.220 mol B) 4.55 mol C) 14.0 mol D) 1.31 * 10³ mol E) None of the above.

Question

Quizplus · Accepted Answer

First, we need to determine the molar mass of NH₃. N = 14.01 g/mol H = 1.008 g/mol S = 32.06 g/mol U = 238.03 g/mol B = 10.81 g/mol 1N + 1H + 1S + 1U + 13B = 14.01 + 1.008 + 32.06 + 238.03 + (13 x 10.81) = 595.28 g/mol Next, we can use the formula: moles = mass / molar mass moles = 77.5 g / 595.28 g/mol = 0.130 mol Therefore, the answer is B: 4.55 mol (rounded to two decimal places).

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How Many Moles of NH₃ Are There in 77