How many grams of sulfur are there in 6.0 g of Fe₂(SO₄)₃?

Name: How many grams of sulfur are there in 6.0 g of Fe 2 (SO 4 ) 3 ?
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Quizplus · Accepted Answer

Fe₂(SO₄)₃ contains 3 moles of sulfur (S) per mole of the compound. The molar mass of Fe₂(SO₄)₃ is approximately 399.88 g/mol, and the molar mass of sulfur is approximately 32.07 g/mol. Therefore, the mass of sulfur in 6.0 g of Fe₂(SO₄)₃ is calculated as follows: (6.0 g / 399.88 g/mol) * (3 * 32.07 g/mol) = 1.44 g.

How Many Grams of Sulfur Are There in 6