Ammonia reacts with diatomic oxygen to form nitric oxide and water vapor: 4NH₃ + 5O₂ $\rarr$ 4NO + 6H₂O
When 20.0 g NH₃ and 50.0 g O₂ are allowed to react, which is the limiting reagent?

Question

Ammonia reacts with diatomic oxygen to form nitric oxide and water vapor: 4NH₃ + 5O₂

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4NO + 6H₂O
When 20.0 g NH₃ and 50.0 g O₂ are allowed to react, which is the limiting reagent?

Quizplus · Accepted Answer

20.0 g NH₃ * (1 mol NH₃/17.03 g NH₃) * (4 mol NO/4 mol NH₃) = 2.35 mol NO50.0 g O₂ * (1 mol O₂/32.00 g O₂) * (4 mol NO/5 mol O₂) = 2.50 mol NOSince 2.35 mol NO < 2.50 mol NO, NH₃ is the limiting reagent.

Ammonia Reacts with Diatomic Oxygen to Form Nitric Oxide and Water