Vanadium(V) oxide reacts with calcium according to the chemical equation below. When 10.0 moles of V₂O₅ are mixed with 10.0 moles of Ca, which is the limiting reagent
V₂O₅(s) + 5Ca(l) $\rarr$ 2V(l) + 5CaO(s)

Question

Vanadium(V) oxide reacts with calcium according to the chemical equation below. When 10.0 moles of V₂O₅ are mixed with 10.0 moles of Ca, which is the limiting reagent
V₂O₅(s) + 5Ca(l)

\rarr

2V(l) + 5CaO(s)

Quizplus · Accepted Answer

To determine the limiting reagent, we need to calculate the amount of product that each reactant can produce. For V₂O₅: 1 mole of V₂O₅ produces 2 moles of V. Therefore, 10.0 moles of V₂O₅ can produce 20.0 moles of V. For Ca: 5 moles of Ca produces 5 moles of CaO. Therefore, 10.0 moles of Ca can produce 10.0 moles of CaO. Since we need 10 moles of CaO to fully react with the 20 moles of V that can be produced by 10 moles of V₂O₅, it is clear that Ca is the limiting reagent. Therefore, the correct answer is B.

Vanadium(V) Oxide Reacts with Calcium According to the Chemical Equation →\rarr→

Vanadium(V) Oxide Reacts with Calcium According to the Chemical Equation $\rarr$